Mastering the Quadratic Function (OLevel's Pure Math)

1. The Basics: Standard Form

A quadratic function is a polynomial of degree 2, generally expressed as:

f(x)= ax2+ bx+c

Where a, b, and c are constants and a0.


2. Features of the Graph

The graph of a quadratic function is a parabola. Its orientation depends on the coefficient a:

  • If a>0, the parabola opens upwards (minimum point).
  • If a<0, the parabola opens downwards (maximum point).

Key features include the y-intercept at (0,c) and the axis of symmetry at:

x=-b2a

3. The Discriminant and the Nature of Roots

To find where the graph crosses the x-axis, we solve ax2+bx+c=0 using the Quadratic Formula:

x= -b±b2-4ac 2a

The expression under the square root, b2-4ac, is called the Discriminant (Δ).

Discriminant Value Nature of Roots Graph Interaction
b2-4ac>0 Two distinct real roots Crosses x-axis twice
b2-4ac=0 One repeated real root Touches x-axis once (tangent)
b2-4ac<0 No real roots Does not touch the x-axis

4. Completing the Square (Vertex Form)

By completing the square, we can rewrite the function in vertex form:

f(x)= a(x-h)2+k

The point (h,k) is the vertex (turning point) of the parabola.


5. Worked Example: Finding the Vertex

Question: Find the coordinates of the turning point for f(x)=2x2-12x+23.

Solution:

  1. Factor out the coefficient of x2 from the first two terms:
    f(x)=2(x2-6x)+23
  2. Complete the square inside the bracket:
    Take half of -6 (which is -3) and square it (9).
    f(x)=2[(x-3)2-9]+23
  3. Expand and simplify:
    f(x)=2(x-3)2-18+23 f(x)=2(x-3)2+5
  4. Identify the Vertex:
    The vertex is at (3,5). Since a=2>0, this is a minimum point.

Summary Checklist

  • Can you identify a, b, and c?
  • Do you know if the parabola opens up or down?
  • Can you calculate the discriminant to find the number of roots?
  • Can you complete the square to find the turning point?

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